Check the access of a file

This is a simple program to check the access of a file (whether it is readable , writable or executable or not).
It uses the standard linux system call access for this purpose.

//Filename : access.c
//To compile : gcc -o acc access.c
//To run : ./acc 

#include <errno.h>
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>

int main (int argc, char* argv[])
{
  char* path = argv[1];
  int rval;

  if(argc != 2 )
  {
    fprintf(stderr,"Usage : %s <file-path>\n",argv[0]);
    exit(0);
  }

  rval = access (path, F_OK);
  if (rval == 0)
    printf ("%s exists\n", path);
  else {
  /* Check file existence. */
    if (errno == ENOENT)
      printf ("%s does not exist\n", path);
  /* Check file access. */
    else if (errno == EACCES)
      printf ("%s is not accessible\n", path);
    return 0;
  }
  /* Check read access. */
  rval = access (path, R_OK);
  if (rval == 0)
    printf ("%s is readable\n", path);
  else
    printf ("%s is not readable (access denied)\n", path);
  /* Check write access. */
  rval = access (path, W_OK);
  if (rval == 0)
    printf ("%s is writable\n", path);
  else if (errno == EACCES)
    printf ("%s is not writable (access denied)\n", path);
  else if (errno == EROFS)
    printf ("%s is not writable (read-only filesystem)\n", path);
  return 0;
}